C++:删除由new创建的指针时的内存问题
我对以下代码有点困惑
int main()
{
int* a = new int{12};
int* b = new int;
b = a;
delete a;
delete b;
return 0;
}
该代码返回一个错误
a.out(27538,0x10ade7e00) malloc: *** error for object 0x7f8c18504160: pointer being freed was not allocated
a.out(27538,0x10ade7e00) malloc: *** set a breakpoint in malloc_error_break to debug
zsh: abort ./a.out
我的问题是,当我删除 a 时,它会自动删除 b 吗?这里的机制是什么,我有点迷路了。
回答
b = a; // here the int that b pointed at "leaks" (you have no way of deleting it)
delete a; // here "a" is deleted first
delete b; // here "a" is deleted a second time (undefined behavior)
当您分配ato的值时b,b先前包含的值(地址,如果您愿意)将被遗忘。双方a并b再分在同一个对象。然后,您失去delete了b指向原始对象的所有可能性。当你然后delete b你实际上尝试删除a第二次。