Ruby 有问题吗？并包括？方法

MCVE（最小、完整、可验证示例）以重现与我相同的问题：

在 rspec 文件位置：

RSpec.describe 'Predicate Enumerable Exercises' do

  describe 'coffee drink exercise' do
    it 'returns true when espresso is included' do
      drink_list = ["milk", "juice", "espresso"]
      expect(coffee_drink?(drink_list)).to be true
    end
  end

  describe 'valid scores exercise' do
    it 'returns true when only one score is a 10' do
      score_list = { easy_to_read: 10, uses_best_practices: 8, clever: 7 }
      perfect_score = 10
      expect(valid_scores?(score_list, perfect_score)).to be true
    end 
  end

end

在实际的函数文件中：

def coffee_drink?(drink_list)
  drink_list.include?("coffee" || "espresso")
end

def valid_scores?(score_list, perfect_score)
  score_list.one?{|score| score == perfect_score}
end

我很难弄清楚我的代码出了什么问题，因为我依赖于内置方法（一个？，包括？）所以我不确定实际问题是什么

我创建了 2 个方法，coffee_drink?(drink_list)并且valid_scores?(score_list, perfect_score).

coffee_drink?获取一个数组，然后仅当它包含单词coffee或时才返回 true espresso。我使用以下内容返回预期：drink_list.include?("coffee" || "espresso")
但是当我espresso在我的列表中并且没有coffee控制台返回时：

哪里drink_list是["milk", "juice", "espresso"]

因为valid_scores?它获取一个数组和整数，并在数组中只有一个值等于该整数时返回 true。但我预计score_list.one?{|score| score == perfect_score}当只有一个值为真时会返回真。相反，我得到：

数组在哪里

score_list = { easy_to_read: 10, uses_best_practices: 8, clever: 7 }

整数是

perfect_score = 10

如果有帮助，我正在使用 ruby​​ 2.7.2p137（2020-10-01 修订版 5445e04352）[x86_64-linux]。

回答

"coffee" || "espresso" #=> "coffee"
# so
drink_list.include?("coffee" || "espresso")
# evaluates to
drink_list.include?("coffee")

drink_list.include?("coffee") || drink_list.include?("espresso")
# or
drink_list.any? { |drink| drink == "coffee" || drink == "espresso" }
drink_list.any?(/\A(coffee|espresso)\z/)
(drink_list & ["coffee", "espresso"]).size.positive? # !(...).empty? also works

score_list.one? { |pair| pair.last == perfect_score }

score_list.one? { |key, value| value == perfect_score }

score_list.values.one? { |score| score == perfect_score  }