c#

我有一个 JSON，例如可以是这样的：

{
   "value":[
      {
         "Name":"Nik",
         "Age":"17",
         "Country":"Germany",
      },
      {
         "Name":"Tom",
         "Age":"20",
         "Country":"Russia",
      },
      {
         "Name":"Sila",
         "Age":"12",
         "Country":"Switzerland",

      }
   ]
}

“姓名”和“年龄”等属性的键是动态的，可以变化。JSON 也可能如下所示：

{
   "value":[
      {
         "Prename":"Nik",
         "Age":"17",
         "Country":"Germany"
         "Car":"Merc"
      },
      {
         "Prename":"Nik",
         "Age":"20",
         "Country":"Russia"
         "Car":"BMW"
      },
      {
         "Prename":"Nik",
         "Age":"12",
         "Country":"Switzerland",
         "Car":"Audi"
      }
   ]
}

重要的是结构，这就是我想用Newtonsoft.Json.

这是我目前的尝试：

var jArray = new JArray();
jArray.Add("Name");
jArray.Add("Nikola");

jArray.Add("Age");
jArray.Add("17");

jArray.Add("Country");
jArray.Add("Germany");

JObject o = new JObject();
o["Value"] = jArray;

string json = o.ToString();

结果：

{
  "Value": [
    "Name",
    "Nikola",
    "Age",
    "17",
    "Country",
    "Germany"
  ]
}

我试图用来自 newtonsoft 网站的这个例子来解决它，但正如你所看到的，它的解释真的很糟糕。

回答

var jArray = new JArray();
var nik = new JObject();
nik["Name"] = "nik";
nik["Age"] = "17";
nik["Country"] ="Germany";

jArray.Add(nik);
JObject o = new JObject();
o["Value"] = jArray;

string json = o.ToString();

    var jArray = new JArray
    {
        new JObject {["Name"] = "nik", ["Age"] = "17", ["Country"] = "Germany"},
        new JObject {["Name"] = "bob", ["Age"] = "32", ["Country"] = "New Zealand"}
    };
    var o = new JObject {["Value"] = jArray};