SwiftUI中的可选@ObservableObject
我想在 SwiftUI 中有一个可选的 @ObservedObject 但我一直收到编译时错误。
Property type 'AModel?' does not match that of the 'wrappedValue' property of its wrapper type 'ObservedObject'
这是一些最小的可重现代码。
import SwiftUI
public struct AView: View {
//MARK: View Model
//Error thrown here.
@ObservedObject var model: AModel?
//MARK: Body
public var body: some View {
Text("(model?.value ?? 0)")
}
//MARK: Init
public init() {
}
}
class AModel: ObservableObject {
let value: Int = 0
}
回答
技术原因是它Optional不是一个类,所以它不能符合ObservableObject.
但是如果你想避免重构对象本身——例如,如果它不在你的控制范围内——你可以这样做:
struct AView: View {
private struct Content: View {
@ObservedObject var model: AModel
var body: some View {
Text("(model.value)")
}
}
var model: AModel?
var body: some View {
if let model = model {
Content(model: model)
} else {
Text("0")
}
}
}