绘制神经网络
我正在尝试用 python 绘制神经网络图,到目前为止我已经能够使用这个脚本。
import matplotlib.pyplot as plt
def draw_neural_net(ax, left, right, bottom, top, layer_sizes):
'''
Draw a neural network cartoon using matplotilb.
:usage:
>>> fig = plt.figure(figsize=(12, 12))
>>> draw_neural_net(fig.gca(), .1, .9, .1, .9, [4, 7, 2])
:parameters:
- ax : matplotlib.axes.AxesSubplot
The axes on which to plot the cartoon (get e.g. by plt.gca())
- left : float
The center of the leftmost node(s) will be placed here
- right : float
The center of the rightmost node(s) will be placed here
- bottom : float
The center of the bottommost node(s) will be placed here
- top : float
The center of the topmost node(s) will be placed here
- layer_sizes : list of int
List of layer sizes, including input and output dimensionality
'''
n_layers = len(layer_sizes)
v_spacing = (top - bottom)/float(max(layer_sizes))
h_spacing = (right - left)/float(len(layer_sizes) - 1)
# Nodes
for n, layer_size in enumerate(layer_sizes):
layer_top = v_spacing*(layer_size - 1)/2. + (top + bottom)/2.
for m in xrange(layer_size):
circle = plt.Circle((n*h_spacing + left, layer_top - m*v_spacing), v_spacing/4.,
color='w', ec='k', zorder=4)
ax.add_artist(circle)
# Edges
for n, (layer_size_a, layer_size_b) in enumerate(zip(layer_sizes[:-1], layer_sizes[1:])):
layer_top_a = v_spacing*(layer_size_a - 1)/2. + (top + bottom)/2.
layer_top_b = v_spacing*(layer_size_b - 1)/2. + (top + bottom)/2.
for m in xrange(layer_size_a):
for o in xrange(layer_size_b):
line = plt.Line2D([n*h_spacing + left, (n + 1)*h_spacing + left],
[layer_top_a - m*v_spacing, layer_top_b - o*v_spacing], c='k')
ax.add_artist(line)
fig = plt.figure(figsize=(12, 12))
ax = fig.gca()
ax.axis('off')
draw_neural_net(ax, .1, .9, .1, .9, [4, 7, 2])
fig.savefig('nn.png')
我想要做的是复制下图中的隐藏层,将隐藏层和输出层节点一分为二来表示节点的内部和激活状态。
有没有办法拆分 plt.circle或添加连接两个半圆以获得这样的表示?