如何在bash中使用grep命令解析以下日期
在 json 文件中给定日期，"ts":"2021-04-23T13:11:57Z"或者"2021-05-05T07:22:54+05:00"我想使用 grep 读取字符串。
需要帮助形成最后一部分的正则表达式，即时区。
我当前的命令
grep -Po '"ts":"K([0-9]{4}-[0-9]{2}-[0-9]{2}T[0-2][0-9]:[0-5][0-9]:[0-5][0-9]+Z对于第一种格式来说很好用，我该如何修改它以使其适用于两种格式。
回答
使用您显示的带有 GNUgrep的 PCRE 选项的示例，您可以尝试遵循正则表达式来匹配两个时间。
grep -oP '(?:"ts":)?"d{4}-d{2}-d{2}T(?:[0-1][1-9]|2[0-4]):(?:[0-4][0-9]|5[0-9])[+:](?:[0-4][0-9]|5[0-9])(?:Z"|+(?:[0-4][0-9]|5[0-9]):(?:[0-4][0-9]|5[0-9])")' Input_file
说明：为以上添加详细说明。
(?:"ts":)? ##In a non-capturing group matching "ts": keeping it optional here.
"d{4}-d{2}-d{2}T ##Matching " followed by 4 digits-2digits-2digits T here.
(?: ##Starting 1st non-capturing group here.
[0-1][1-9]|2[0-4] ##Matching 0 to 19 and 20 to 24 here to cover 24 hours.
): ##Closing 1st non-capturing group followed by colon here.
(?: ##Starting 2nd non-capturing group here.
[0-4][0-9]|5[0-9] ##Matching 00 to 59 for mins here.
) ##Closing 2nd non-capturing group here.
[+:] ##Matching either + or : here.
(?: ##Starting 3rd capturing group here.
[0-4][0-9]|5[0-9] ##Matching 00 to 59 for seconds here.
) ##Closing 3rd non-capturing group here.
(?: ##Starting 4th non-capturing group here.
Z"|+ ##Matching Z" OR +(literal character) here.
(?: ##Starting non-capturing group here.
[0-4][0-9]|5[0-9] ##Matching 00 to 59 here.
) ##Closing non-capturing group here.
: ##Matching colon here.
(?: ##Starting non-capturing group here.
[0-4][0-9]|5[0-9] ##Matching 00 to 59 here.
)" ##Closing non-capturing group here, followed by "
) ##Closing 4th non-capturing group here.