如何使浮点数显示-0也显示为0？
如果我将浮点 0 除以负值，则会显示 -0，这很不方便。我怎样才能摆脱这个问题？
float a = 0;
std::cout << a / (-1);
我试图检查一个数字是否等于 -0 以及该条件是否为真，将变量乘以 -1。这不起作用，因为 0 等于 -0。
回答
Writing a + 0.0f gets rid of the signed zero for a float type a.
(This is defined by IEEE754 and is a standard trick well-known to numericists.)
So if you have an expression that might yield a signed zero, append 0.0f to the end:
std::cout << a / (-1) + 0.0f;