当数组中没有任何内容时,如何从数组eltype中删除Nothing?
例如,如果函数的输出(例如indexin)具有Vector{Union{Nothing, Int64}}类型,
但事先知道只会输出值(没有nothing)。
并且这个输出应该被馈送到另一个
对于这种类型有问题的函数,但是对于一个简单的Int64.
说
julia> output = Union{Nothing, Int64}[1, 2] # in practice, that would be output from a function
2-element Vector{Union{Nothing, Int64}}:
1
2
如何将该输出转换为数组Int64?
以下在这种情况下有效,并且可以收集在一个函数中,但必须有一种更优雅的方式。
julia> subtypes = Base.uniontypes(eltype(output))
2-element Vector{Any}:
Nothing
Int64
julia> no_Nothing = filter(!=(Nothing), subtypes)
1-element Vector{Any}:
Int64
julia> new_eltype = Union{no_Nothing...}
Int64
julia> Array{new_eltype}(output)
2-element Vector{Int64}:
1
2
回答
尝试something:
julia> output = Union{Nothing, Int64}[1, 2]
2-element Vector{Union{Nothing, Int64}}:
1
2
julia> something.(output)
2-element Vector{Int64}:
1
2
- `something` in this case works, but in general it would unwrap `Some` if it were present in the array so it is not ideal. A general approach to automatic `eltype` narrowing AFAICT is to call `identity.(output)` or just `[v for v in output]`.