计算字符串C++中的辅音的逻辑错误
所以我试图计算元音,辅音和特殊字符。我得到了元音和特殊部分的工作,但不是辅音。这是代码;
#include <iostream>
using namespace std;
void characterType(string);
int main()
{
string input = "Testing a sentence.";
characterType(input);
}
void characterType(string input)
{
int vowel, consonant, special = 0;
for (int i = 0; i < input.length(); i++)
{
char character = input[i];
if((character >= 'a' && character <= 'z') ||(character >= 'A' && character <= 'Z'))
{
character = tolower(character);
if (character == 'a' || character == 'e' || character == 'i' || character == 'o' || character == 'u')
{
vowel++;
}
else
{
consonant++;
}
}
else
{
special++;
}
}
cout<< "Vowels: " << vowel << endl;
cout<< "Consonant: " << consonant << endl;
cout<< "Special Character: " << special << endl;
}
这是输出;
我似乎无法弄清楚,有人知道吗?
回答
定义
int vowel, consonant, special = 0;
仅初始化special为0. 其他两个变量未初始化,将具有不确定的值。
您需要显式初始化您想要具有特定初始值的所有变量:
int vowel = 0, consonant = 0, special = 0;
这就是为什么许多人建议每个语句只定义一个变量的原因:
int vowel = 0;
int consonant = 0;
int special = 0;