如何将16字节的内存加载到Rust__m128i中?
我正在尝试将 16 字节的内存加载到模块中的__m128i类型中std::arch:
#[cfg(all(target_arch = "x86_64", target_feature = "sse2"))]
use std::arch::x86_64::__m128i;
fn foo() {
#[cfg(all(target_arch = "x86_64", target_feature = "sse2"))]
use std::arch::x86_64::_mm_load_si128;
unsafe {
let mut f: [i8; 16] = [0; 16];
f[0] = 5;
f[1] = 66;
let g = _mm_load_si128(f as *const __m128i);
}
}
fn main() {
foo();
}
我的代码导致错误:
error[E0605]: non-primitive cast: `[i8; 16]` as `*const __m128i`
--> src/main.rs:12:32
|
12 | let g = _mm_load_si128(f as *const __m128i);
| ^^^^^^^^^^^^^^^^^^^ an `as` expression can only be used to convert between primitive types or to coerce to a specific trait object
从文档中不清楚如何使用_mm_load_si128从现有内存或现有类型加载字节。我希望能够__m128i 通过加载内部函数从某些现有类型加载字节。
回答
通过负载内在
内在函数是 docs 中列出的函数。模块中的示例涵盖了从内存加载的具体示例:
let invec = _mm_loadu_si128(src.as_ptr() as *const _);let invec = _mm_loadu_si128(src.as_ptr() as *const _);
对于您的情况:
也可以看看:
arch::x86_64::_mm_loadu_si128