与NumPy实例调用`__bool__`的相等性比较

我定义了一个类，它的__ge__方法返回自身的一个实例，并且__bool__不允许调用其方法（类似于 Pandas Series）。

为什么X.__bool__在 during 中被调用np.int8(0) <= x，而不是在其他任何示例中被调用？谁在调用它？我已经阅读了数据模型文档，但我还没有在那里找到答案。

import numpy as np
import pandas as pd

class X:
    def __bool__(self):
        print(f"{self}.__bool__")
        assert False
    def __ge__(self, other):
        print(f"{self}.__ge__")
        return X()

x = X()

np.int8(0) <= x

# Console output:
# <__main__.X object at 0x000001BAC70D5C70>.__ge__
# <__main__.X object at 0x000001BAC70D5D90>.__bool__
# Traceback (most recent call last):
#   File "<stdin>", line 1, in <module>
#   File "<stdin>", line 4, in __bool__
# AssertionError

0 <= x

# Console output:
# <__main__.X object at 0x000001BAC70D5C70>.__ge__
# <__main__.X object at 0x000001BAC70D5DF0>

x >= np.int8(0)

# Console output:
# <__main__.X object at 0x000001BAC70D5C70>.__ge__
# <__main__.X object at 0x000001BAC70D5D30>


pd_ge = pd.Series.__ge__
def ge_wrapper(self, other):
    print("pd.Series.__ge__")
    return pd_ge(self, other)

pd.Series.__ge__ = ge_wrapper

pd_bool = pd.Series.__bool__
def bool_wrapper(self):
    print("pd.Series.__bool__")
    return pd_bool(self)

pd.Series.__bool__ = bool_wrapper


np.int8(0) <= pd.Series([1,2,3])

# Console output:
# pd.Series.__ge__
# 0    True
# 1    True
# 2    True
# dtype: bool