两个线程需要按此顺序打印-

Thread1:0    
Thread2:::0    
Thread1:1    
Thread2:::1    
Thread1:2    
Thread2:::2    
Thread1:3    
Thread2:::3
Thread1:::4    
Thread2:::4    
.    
.    
.   
Thread1:100    
Thread2:::100
...

目前这是我的代码，不知何故它卡住了。. 不知道为什么它没有按预期运行

public class Solution{
    private volatile boolean isOneTurn;

    public Solution(){
        isOneTurn = true;
    }

    public void test(){
        Thread t1 = new Thread(new MyThread1("Thread1"));
        Thread t2 = new Thread(new MyThread2("Thread2"));

        t1.start();
        t2.start();
    }

    class MyThread1 implements Runnable {
        public String name;

        public MyThread1(String name) {
            this.name = name;
        }
        @SneakyThrows
        @Override
        public void run() {
            for (int i = 1; i <= 100; i++) {
                synchronized (this) {
                    if (!isOneTurn){
                        this.wait();
                    }

                    System.out.println(name + "-" + i);
                    isOneTurn = false;
                    this.notifyAll();
                }
            }
        }
    }


    class MyThread2 implements Runnable {
        public String name;

        public MyThread2(String name) {
            this.name = name;
        }
        @SneakyThrows
        @Override
        public void run() {
            for (int i = 1; i <= 100; i++) {
                synchronized (this) {
                    if (isOneTurn){
                        this.wait();
                    }

                    System.out.println(name + "-" + i);
                    isOneTurn = true;
                    this.notifyAll();
                }
            }
        }
    }
}

我知道那里有很多类似的问题。但我只是想知道为什么我的代码没有按预期工作。

回答