用 C 编写一个程序来计算从命令行传递的数字的阶乘。阶乘必须在一个名为 computeFact() 的单独函数中计算，该函数具有以下原型： int computeFact(int,…);

#include <stdarg.h>
#include <stdio.h>
#include<stdlib.h>
int computeFact(int, ...);
int main(int argc, char *argv[]) 
{
  if (argc < 2) 
  {
    printf("Invalid!");
  } else {
    for (int i = 1; i < argc; i++)
    {
      int n = atoi(argv[i]);
      printf("Factorial of %d is %dn", n, computeFact(n));
    }
  }
  printf("n");./
  return 0;
}
int computeFact(int num, ...) 
{
  va_list valist;
  int fact = 1;

  va_start(valist, num);
  for (int i = 0; i < num; i++) 
  {
    int x=va_arg(valist, int);
    if(x==0)
      return 1;
    else
    {
    for(int j = 1; j <= x; j++)
       fact=fact*j;
    return fact;
    }
  }
  va_end(valist);
}

输出如下：

~$ ./1 1 2 3 4 5 6 7 8 9 10
Factorial of 1 is 1
Factorial of 2 is 2
Factorial of 3 is 6
Factorial of 4 is 24
Factorial of 5 is 120
Factorial of 6 is 720
Factorial of 7 is 5040
Factorial of 8 is 40320
Factorial of 9 is 362880
Factorial of 10 is 1

~$ ./1 0
Factorial of 0 is 1

~$ ./1 99
Factorial of 99 is 362880

~$ ./1 98
Factorial of 98 is 40320

~$ ./1 5
Factorial of 5 is 120

我认为将 string 转换为 int 存在一些错误，因为只有两位数中的最后一位用于计算阶乘，但我无法确定我的代码中究竟要更正什么。

回答

int computeFact(int num, ...) 
{
  int fact = 1;

  int x=num;
  if(x==0)
    return 1;
  else
  {
    for(int j = 1; j <= x; j++)
      fact=fact*j;
    return fact;
  }
}