C中的嵌套if语句-为什么它不评估最后一个elseif?
else if当您分配给choicevalue时,以下代码不会执行最后一条语句3。
#include<stdio.h>
#include<stdlib.h>
int main() {
puts("Specify with a number what is that you want to do.");
puts("1. Restore wallet from seed.");
puts("2. Generate a view only wallet.");
puts("3. Get guidance on the usage from within monero-wallet-cli.");
unsigned char choice;
choice = getchar();
if ( choice == '1' ) {
system("nice -19 ~/monero-x86_64-linux-gnu-v0.17.2.0/monero-wallet-cli --testnet --restore-deterministic-wallet");
exit(0);
}
else if ( choice == '2' ) {
system("nice -19 ~/monero-x86_64-linux-gnu-v0.17.2.0/monero-wallet-cli --testnet --generate-from-view-key wallet-view-only");
exit(0);
}
else if ( choice == '3' ) {
puts("Specify with a number what is that you want to do.");
puts("1. Get guidance in my addresses and UTXOs");
puts("2. Pay");
puts("3. Get guidance on mining.");
unsigned char choicetwo = getchar();
if ( choicetwo == '1' ) {
printf("Use 33address all 33 to get all your addresses that have any balance, or that you have generated at this session.");
printf("Use 33balance 33 to get your balance");
printf("Use 33show_transfers 33 to get ");
printf("Use 33show_transfers 33 out to get ");
printf("Use 33show_transfers in 33 to get your balance");
}
}
return 0;
}
当我输入时,我得到以下输出3:
Specify with a number what is that you want to do.
1. Restore wallet from seed.
2. Generate a view only wallet.
3. Get guidance on the usage from within monero-wallet-cli.
3
Specify with a number what is that you want to do.
1. Get guidance in my addresses and UTXOs
2. Pay
3. Get guidance on mining.
我真的被阻止了,有些东西丢失了,我不知道为什么它不继续第二次接受用户的输入。
回答
当您为第一个输入输入“3”时,您实际上是在输入两个字符:字符'3'和换行符。第一个getchar函数从输入流中读取“3”,第二个函数读取换行符。
接受第一个输入后,您需要getchar循环调用,直到读取换行符以清除输入缓冲区。
choice = getchar();
while (getchar() != 'n');