使用rand()函数的无限循环，因为一个mutatorc++

我有一个 Student 类，它有一个表示标志的私有成员。我也有一个标志设置器功能。

#include <iostream>
#include <cstring>


using namespace std;

class Student
{
private:
    string name;
    int flag;
public:
    Student(const string stname)
    :name(stname),flag(0)
    {
        cout << "Student with name " << name << " has been constructed!" << endl;
    };
    ~Student()
    {
        cout << "Student with name " << name << " to be destroyed!" << endl;
    };
    int get_flag();
    void set_flag(const int number);
};

以下是功能：

void Student::set_flag(const int number){  flag = number;}

int Student::get_flag(){  return flag;}

我主要尝试做的是选择一个随机数来表示循环数量和另一个随机数来选择要更改哪些学生对象标志。

编码：

#include <iostream>
#include <cstring>
#include <cstdlib>
#include <ctime>

using namespace std;

int main()
{
    string name;
    Student* students[44];
    for(int i=0; i<44; i++)
    {
       cin >> name;
       students[i] = new Student(name);
    }

   int how_many , which;
   srand (time(NULL));
                                //0-44 students can be changed
   how_many = rand() % 44 + 1; //how many students are going to be changed
   int j=1;
   while(j <= how_many) //which students are going to be changed
   {
       //i have 44 students so students array indexes range 0-43
       which = rand() % 43;
       if((students[which])->get_flag() == 1) continue;
       //if the student is not already picked to be changed
       if((students[which])->get_flag() != 1)
       {
          (students[which])->set_flag(1);
          j++;
        }
   }


    for(int i=0; i<44; i++) delete students[i];
}

为什么会导致死循环。真心好奇。看起来我真的没有做错什么。

回答

how_many = rand() % 44 + 1;

which = rand() % 43;