使用mips组件检查回文

.data

org_str: .space 256
rev_str: .space 256
str: .asciiz "Enter the Line: "
pal: .asciiz "palindrome"
not_pali: .asciiz "Not palindrome"

.text 
.globl main
main:
    
    
    li $v0, 4
    la $a0, str
    syscall
    
    # Taking String from the user
    li $v0, 8
    la $a0, org_str
    li $a1, 256
    syscall
    
    # Initilize $t0 and $t2
    li  $t0, 0
    li  $t1, 0
    
loop_len:
    add $t1, $a0, $t0
    lb  $t2, 0($t1) # Load the data in the byte in $t2
    beqz    $t2, len_exit   # Loop till $t2 reaches zero
    addiu   $t0, $t0, 1 # increment of the counter
    j   loop_len
len_exit:

    #Return $t0 to the last Charater
    subi $t0, $t0, 1
    li $s0, 0   # Initialize variable
    addi $s0, $t0, 0    # Save the length of the String
    
    # Load the original string in $t2
    la $t2, org_str
    
    # Intialize i and j
    li $t1, 0   # i 
    li $t3, 0   # j
    
reverse_loop:
    add $t3, $t2, $t0   # $t2 is the base address
    lb $t4, 0($t3)      # load a byte
    beqz $t4, exit      # go to the exit if null was found
    sb $t4, rev_str($t1)    # Overwrite the byte
    addi $t0, $t0, -1   # decrement of j by 1 (j--)
    addi $t1, $t1, 1    # increment of i by one (i++)
    j reverse_loop      # Loop until we reach the length of the String
exit:
    
    li $t0, 0
    li $t4, 0
    li $t7, 0
    
CheckChar_loop:
    
    lb $t4, org_str($t0)
    lb $t7, rev_str($t0)
    
    beq $t4, $zero, exit_1  # go to the exit if null was found
    bne $t4, $t7, not_pal   # if $t7 and $t4 not equal
    addi $t0, $t0, 1    # increment of i by 1 (i++)
    j CheckChar_loop
exit_1:

    #li $v0, 1
    #addi $a0, $t0, 0
    #syscall

    li $v0, 4
    la $a0, pal
    syscall

    #Exit the program
    li $v0, 10
    syscall
    
not_pal:
    
    #li $v0, 1
    #addi $a0, $t0, 0
    #syscall
    
    li $v0, 4
    la $a0, not_pali
    syscall
    
    
    #Exit the program
    li $v0, 10
    syscall
    
.end main

我正在尝试检查回文。因此，我们的想法是反转字符串并在每个索引处检查反转字符串中的字符是否与原始字符串相同。我试图检查 org_str 是否等于 rev_str 但它每次都以 $t7 和 $t4 的形式存在，即使它们相等。rev_str 是 org_str 的反转字符串。

回答

    int s0 = 0;   // <--- this initialization is pointless 
    s0 = t0 - 1;  // since s0 is immediately repurposed with a new value here