pysparkpy4j.Py4JException:Methodand([classjava.lang.Integer])不存在
有人可以帮助我了解以下错误吗,我是 PySpark 的新手,开始学习了。
当我用谷歌搜索时,出现以下错误,当我们比较不同类型的数据类型时,我确实有一个名为salary的列作为整数列?为什么我仍然收到此错误。
>>> df.printSchema()
root
|-- Firstname: string (nullable = true)
|-- middlename: string (nullable = true)
|-- lastname: string (nullable = true)
|-- dob: string (nullable = true)
|-- sex: string (nullable = true)
|-- salary: integer (nullable = true)
|-- CopiedColumn: integer (nullable = true)
|-- Country: string (nullable = false)
|-- anotherColumn: string (nullable = false)
>>> df.show()
+---------+----------+--------+----------+---+------+------------+-------+-------------+
|Firstname|middlename|lastname| dob|sex|salary|CopiedColumn|Country|anotherColumn|
+---------+----------+--------+----------+---+------+------------+-------+-------------+
| James| | Smith|1991-04-01| M|300000| -300000| India|Another value|
| Michael| Rose| |2000-05-19| M|400000| -400000| India|Another value|
| Robert| |Williams|1978-09-05| M|400000| -400000| India|Another value|
| Maria| Anne| Jones|1967-12-01| F|400000| -400000| India|Another value|
| Jen| Mary| Brown|1980-02-17| F| -100| 100| India|Another value|
+---------+----------+--------+----------+---+------+------------+-------+-------------+
>>> df.withColumn("lit_value2", when(col("salary") >=400000 & col("salary") <= 500000,lit("100")).otherwise(lit("200"))).show()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/opt/mapr/spark/spark/python/pyspark/sql/column.py", line 115, in _
njc = getattr(self._jc, name)(jc)
File "/opt/mapr/spark/spark/python/lib/py4j-0.10.7-src.zip/py4j/java_gateway.py", line 1257, in __call__
File "/opt/mapr/spark/spark/python/pyspark/sql/utils.py", line 63, in deco
return f(*a, **kw)
File "/opt/mapr/spark/spark/python/lib/py4j-0.10.7-src.zip/py4j/protocol.py", line 332, in get_return_value
py4j.protocol.Py4JError: An error occurred while calling o138.and. Trace:
py4j.Py4JException: Method and([class java.lang.Integer]) does not exist
at py4j.reflection.ReflectionEngine.getMethod(ReflectionEngine.java:318)
at py4j.reflection.ReflectionEngine.getMethod(ReflectionEngine.java:326)
at py4j.Gateway.invoke(Gateway.java:274)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:238)
at java.lang.Thread.run(Thread.java:748)
回答
您需要将条件括在括号中:
when((col("salary") >= 400000) & (col("salary") <= 500000), lit("100"))
否则,由于运算符优先级 -&高于>=.
col("salary") >= (400000 & col("salary")) <= 500000
这是没有意义的,并给出了你得到的错误。
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