有没有办法使用sed替换除引号中的逗号之外的所有逗号
# Director, Movie Title, Year, Comment
Ethan Coen, No Country for Old Men, 2007, none
Ethan Coen, "O Brother, Where Art Thou?", 2000, none
就像在这里，引号外的逗号必须替换为|.
Ethan Coen| "O Brother, Where Art Thou?"| 2000| none
我确实尝试过这个命令
sed -e 's/,(?=(?:[^"]*"[^"]*")*[^"]*$)/|/g',
首先匹配这些字符串，把我收到 RE 错误：重复运算符操作数无效
我不知道如何将 re 转换为 shell 和正则表达式的全新内容，我将不胜感激
回答
您可以尝试使用此gnu awk命令FPAT使用自定义正则表达式拆分字段：
awk -v OFS='|' -v FPAT=' *"[^"]*"|[^",]+' '{$1=$1} 1' file
# Director| Movie Title| Year| Comment
Ethan Coen| No Country for Old Men| 2007| none
Ethan Coen| "O Brother, Where Art Thou?"| 2000| none
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